When
f(x)=%26gt; x^2 - 1 for x%26lt;0 or x%26gt;0
=%26gt; 0 for x=0
I have been staring at this problem for 20 minutes and have no idea what to do,I am losing my mind!
State d x values 4 w/c dis piecewiseDefinedFunction is discontinuous%26amp;list d conditionOfcontinuity dat dontHold
Condition of continuity is that limit at x-%26gt;-0 is equal to limit at x-%26gt;+0 and equal to f(0).
Limit at x-%26gt;-0 and x-%26gt;+0 is equal to 0^2 - 1 = -1, while f(0) = 0.
So last condition does not hold and function is discontinuous.
Reply:it is discontinous at x=1/rt(2).......as the lim x-%26gt;0+ is not equal to lim x-%26gt;0-
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